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  3. OpenCloudOS高效的容器镜像按需加载和去重挑战赛
OpenAtomGeneral MLIntermediateRegistration unverified

OpenCloudOS高效的容器镜像按需加载和去重挑战赛

A intermediate general ml competition requiring roughly 12–40 hours for an end-to-end practice run.

Difficulty
Intermediate
Estimated effort
12–40 hours
Registration deadline
To be confirmed
Compute
CPU only
OverviewPreparationSource

Overview

Who this competition fits

适合已有 Linux 存储和容器运行时开发经验的开发者,尤其是熟悉 EROFS/ext4、Containerd 插件或 OCI 容器镜像格式的人。个人和团队均可参加,页面明确参赛对象不受限制,但作品需要能实现可运行的系统方案。

Read the original official blurb
OpenCloudOS是聚焦云原生操作系统的开源社区,社区关注到容器镜像的OCIv1标准采用分层和tar格式存储存在显著缺陷,讨论已久的OCIv2标准将延迟加载和减少数据重复列为核心挑战。请设计并实现一个不依赖fuse、保留层、数据去重的按需加载方案。 Official category: 实战竞技赛. Organizers: OpenCloudOS,腾讯云. Competition code: 2025OAC011. Participants: 5.

Preparation

From registration to a first submission

  1. 01

    Linux 存储子系统

  2. 02

    Containerd 插件开发

  3. 03

    OCI 镜像规范

  4. 04

    文件与块级去重算法

  5. 05

    容器镜像构建与运行时

  6. 06

    Git 仓库与开源许可证

Before you commit: 难点在于同时满足几个彼此牵制的系统约束:不依赖 FUSE,又要保留 OCI v1 镜像层、实现按需加载,并完成文件或块级去重及运行时兼容。最终还需提交全量可编译代码、测试脚本和量化启动加速、资源节省效果的技术报告。

Source

How this page was assembled

Competition information is structured from the official page. Scores are platform estimates for decision support; official rules take precedence.

Official competition page
OpenAtom
Last checked
Jul 21, 2025

Entry assessment

est.
48

Prepare before joining

Overall fit estimate

Beginner fit48/100
Learning value60/100

Confirm eligibility and time commitment before moving into formal preparation.

Entry eligibility needs official confirmation

Open official pageSign in to saveOpen guide

Data and review state

Separate what is confirmed from what still needs review. Official rules and deadlines win.

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Source page verifiedMetric confirmedReviewed
Source published
Jul 21, 2025
Source created
Jul 21, 2025
Published on this site
Jul 21, 2026

Official metric is not published on the OpenAtom competition listing; verify scoring on the competition page.

reward_value_usd is a rough CNY→USD estimate (×0.14) for ranking only; use reward_summary for the official prize text.